Looking for classes? Ksquare Career Institute, Bengaluru →
Field due to straight wires
Concepts tested here
- Perpendicular fields
All Questions
2014 AIPMT 1 question
-
Two identical long conducting wires AOB and COD are placed at right angle to each other, with one above other such that 'O' is their common point for the two. The wires carry $I_1$ and $I_2$ currents respectively. Point 'P' is lying at distance 'd' from 'O' along a direction perpendicular to the plane containing the wires. The magnetic field at the point 'P' will be:The fields of the two wires at P are perpendicular: $B = \sqrt{B_1^2 + B_2^2}$
$B = \sqrt{\left(\frac{\mu_0I_1}{2\pi d}\right)^2 + \left(\frac{\mu_0I_2}{2\pi d}\right)^2} = \frac{\mu_0}{2\pi d}\sqrt{I_1^2 + I_2^2}$
