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System of Particles and Rotational Motion
Equilibrium of a Rigid Body – Moments
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Concepts tested
- balancing a loaded rod
All Questions
2021 1 question
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A uniform rod of length 200 cm and mass 500 g is balanced on a wedge placed at 40 cm mark. A mass of 2 kg is suspended from the rod at 20 cm and another unknown mass $m$ is suspended from the rod at 160 cm mark as shown in the figure. Find the value of $m$ such that the rod is in equilibrium. ($g=10\ m/s^2$)

Weight of the rod (0.5 kg) acts at its centre (100 cm), i.e. 60 cm from the wedge. The 2 kg mass is 20 cm from the wedge and m is 120 cm from it.
Balancing torques about the wedge: $2g \times 20 = 0.5g \times 60 + mg \times 120$ $40 = 30 + 120m \Rightarrow m = \frac{1}{12}$ kg
