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Rotational KE and angular momentum
Concepts tested here
- equal-ke-angular-momentum
All Questions
2016 Phase II 1 question
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Two rotating bodies A and B of masses m and 2m with moments of inertia $I_A$ and $I_B$ ($I_B > I_A$) have equal kinetic energy of rotation. If $L_A$ and $L_B$ be their angular momenta respectively, then:
$K = L^2/2I$; for equal K, larger I means larger L.
$K_A = K_B \Rightarrow \frac{L_A^2}{2I_A} = \frac{L_B^2}{2I_B}$
$\because I_B > I_A$, $\therefore L_A^2 < L_B^2 \Rightarrow L_A < L_B$
