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System of Particles and Rotational Motion
Moment of Inertia of a Rod
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- Moment of inertia of thin rod about perpendicular bisector
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2024 1 question
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The moment of inertia of a thin rod about an axis passing through its mid point and perpendicular to the rod, is 2400 g cm$^2$. The length of the 400 g rod is nearly:Moment of inertia of a thin rod about an axis through its mid-point, perpendicular to the rod: $I = \frac{ML^2}{12}$ $\frac{400 \times L^2}{12} = 2400$ $L^2 = \frac{12 \times 2400}{400} = 72$ $L = \sqrt{72} \approx 8.5$ cm